I’d like to calculate the deformations of a square composite structure subjected to uniaxial tension at an angle of 45°.
Assuming that the square composite structure is symmetrical vertically and horizontally, the analysis should be possible with ① in the diagram above.
So what about uniaxial tension in the 45° oblique direction (②)?
First, the program was developed assuming that the quadrangle is subjected to uniaxial tension so that the strain is uniform in the 45° diagonal direction.
It is assumed here that the nodal displacements can move arbitrarily on the four-sided boundary after deformation.
How can this code be improved to perform the analysis described above? 250217_FF++_COMMUNITY.edp (8.3 KB)
I think the boundary condition would be a combination of enforced displacement, roller boundary, and then a periodic boundary conditions, is there any way to do that?
I love FF++ because it is inexpensive, offline, and can be used anytime, anywhere.
Thank you very much for your efforts to improve and maintain the development of FF++.
Thank you for your reply.
Let me correct my question as it seems to have been misunderstood.
In Analysis 1, the “external boundary” goes from a square to a rectangle with strain 1, but the internal two-phase structure deforms freely.
That is, the exterior boundary is subject to forced displacement and free to move on the boundary (roller boundary).
For this reason, the boundary conditions are given as in (1) in the figure
I would like to know what happens if this is accompanied by strain 1 at oblique 45.
Rectangular exterior boundaries are simultaneously subjected to forced displacement and roller boundary conditions that result in a rhombic shape?
