D_N_Sarkar
(D N Sarkar)
1
Say I have the following code:
int nn = 50;
mesh Th = square(nn, nn);
fespace Vh(Th, P1);
Vh u;
u = sin(x);
I can get the maximum value of ‘u’ by:
real maxValueU = u[].max;
How do I get the values of x and y coordinates where maximum value of ‘u’ occurs?
yes but be careful because the max could be not unique.unc
the method imax give the dof number
int dofmaxValueU = u[].imax;
Now for P1 finite element the dof are vertices with same numbering so
Th(dofmaxValueU).x
Th(dofmaxValueU).y
given the coordinate.