# Weighting integral by mesh area

**URL:** <https://community.freefem.org/t/weighting-integral-by-mesh-area/1114>\
**Category:** General Discussion\
**Created:** [July 23, 2021, 6:51am UTC](https://community.freefem.org/t/weighting-integral-by-mesh-area/1114 "2021-07-23T06:51:37Z")\
**Posts on this page:** 1\
**Page:** 1

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**Author:** ![zese](https://yyz2.discourse-cdn.com/flex030/user_avatar/community.freefem.org/zese/32/917_2.png) [@zese](https://community.freefem.org/u/zese)\
**Post date:** [July 23, 2021, 6:51am UTC](https://community.freefem.org/t/weighting-integral-by-mesh-area/1114/1 "2021-07-23T06:51:37Z")

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Dear all,

I have an integral as int2d(th)(u\*.v) in which \* is the complex conjugate and I want it for normalizing u=u/ int2d(th)(u\*.v) . I want to weight it by element size. I am not sure when I write it simply as int2d(th)(u\*.v) the element size interferes or not. should I write it as int2d(th)(u\*.v. th.area)?

Best regards